Need help ASAP Will mark BRAINLIST and thanks only for correct answers

1.What is the correct way a cell phone call goes out?

-The phone call goes out, transmits through microwaves, then moves to the central hub. Then the signals go to the nearest tower to the receiver of the call.

-The phone call goes out, transmits through radio waves, then moves to the central hub. Then the signals go to the nearest tower to the receiver of the call.

-The phone call goes out, transmits through microwaves, then moves to the tower. Then the signals go to the nearest hub to the receiver of the call.

2.Which property of AM frequencies allow them to travel over long distances?

-high amplitude
-high energy
-constant velocity
-long wavelength

3.what types of waves do cell phones use?
-radio waves
-gamma rays
-microwaves

1. The correct way a cell phone call goes out is;

The phone call goes out, transmits through radio waves, then moves to the central hub. Then the signal go to the nearest tower to the receiver of the call

2. Long wavelength

3. Microwave

Explanation:

1. When making a call through a cell phone, the speech made is digitized such that it is converted to electrical signals which are then converted into number strings that are transmitted out of the antenna of the phone as radio waves which are then picked up by the closest cellphone tower mast which then transmit the signal to the applicable central hub from where the signal is transmitted to the tower closest to the intended call receiver

Therefore, the correct option is that the phone call goes out, transmits through radio waves, then moves to the central hub. Then the signal go to the nearest tower to the receiver of the call

2. The property of AM frequencies that allow them to travel over long distances is long wavelength

The frequency of AM radio waves is between 540 kHz and 1600 kHz, which can be propagated as ground wave or by the ionosphere at night

3. Cell phones makes use of the subcategory of microwave which is the super high frequency (SHF) band which with a range of 3 GHz to 30 GHz

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000

thermal energy is the answer