A power cable has a resistance of 0.22 and carries
a current of 20A what is power lost as heat?

88 Watts

Explanation:

From the question given above, the following data were obtained:

Resistance (R) = 0.22 Ohm

Current (I) = 20 A

Power (P) =.?

P = IV (1)

From ohm's law,

V = IR (2)

Substitute the value of V in equation (2) into equation (1)

P = IV

V = IR

P = I(IR)

P = I²R

With the above formula (i.e P = I²R), we can obtain the power lost to heat as follow:

Resistance (R) = 0.22 Ohm

Current (I) = 20 A

Power (P) =.?

P = I²R

P = 20² × 0.22

P = 400 × 0.22

P = 88 Watts

Thus, the power lost to heat is 88 Watts.

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explanation: