Find the sum of these four vector forces: 12.0 n to the right at 35.0° above the horizontal, 31.0 n to the left at 55.0° above the horizontal, 8.40 n to the left at 35.0° below the horizontal, and 24.0 n to the right at 55.0° below the horizontal. (hint: make a drawing of this situation and select the best axes for x and y so that you have the least number of components. then add the vectors, using the component method.)

Aforce of 34.5 newtons is applied to an object at an angle of 45 º with the horizontal. what is the force acting on the object in the horizontal direction?

What is the earliest point in the universe that we can observe? why can’t we see back further than this?

1point) a skydiver weighing 130 lb (including equipment) falls vertically downward from an altitude of 14,000 ft and opens the parachute after 20 s of free fall. assume that the force of air resistance, which is directed opposite to the velocity, is of magnitude 0.85|v|0.85|v| when the parachute is closed and is of magnitude 17|v|17|v| when the parachute is open, where the velocity vv is measured in ft/s. assume that acceleration due to gravity has magnitude 32 ft/s/s; remember that weight is the product of mass and gravitational acceleration. find the speed of the skydiver when the parachute opens. speed is 150.6121788 ft/s find the skydiver's height when the parachute opens. height is 2338.98591 ft find the limiting velocity vlvl after the parachute opens. (think about whether this should be positive or negative.) vl=vl= 7.647 ft/s