An object with a mass of 32 kg has an initial energy of 500 J. At the end of the experiment, the velocity of the object is recorded as 5.1 m/s. If the object travelled 50 m to get to this point, what was the average force of friction on object during the trip? Assume no potential energy. Show all work

Explanation:
the concept of conservation of the mechanical nerve
initial
Em₀ = 500 J
The energy is totally kinetic
Em₀ = K = ½ m v₀²
v₀ =
v₀ = √ (2 500/32)
v₀ = 5.59 m / s
v² = v₀² - 2 a x
the negative sign is because its stopping
a =
a = (5.59² - 5.1²) / 2 50
a = 0.0524 m / s²
Newton's second law
F = ma
F = 32 0.0524
F = 1.68 N

Velocity=total displacement/timefrom house to store is 500 from store to neighbor is 200 therefore total displacement=500+200=700metrestherefore,700metres/910seconds=0.8metres per second