1. A ball is thrown straight up. if the launch velocity is 15 m/s, at what velocity will the ball return to the thrower's hand? 2. A boat moves across a river going 18 m/s. At the same time there is a current flowing at a right angle to the boat at 6 m/s. What is the resulting velocity of the boat?

1) The velocity of the ball return to the thrower's hand is -15 meters per second.

2) The resulting velocity of the boat is .

Explanation:

1) Let suppose that ball experiments a free fall, that is an uniform accelerated motion, in which effects from gravity and Earth's rotation can be neglected. The velocity of the ball is represented by the following equations of motion:

Position

(1)

Velocity

(2)

Where:

- Time, measured in seconds.

- Gravitational acceleration, measured in meters per square second.

- Initial velocity of the ball, measured in meters per second.

- Final velocity of the ball, measured in meters per second.

From (1), we get the time when the ball returns to the thrower's hand:

And then we apply this result in (2):

(3)

Then, the velocity of the ball return to the thrower's hand is -15 meters per second.

2) The resulting velocity of the boat () is represented by the vectorial sum of the velocity of the boat relative to the river () and the velocity of the river (), both measured in meters per second, that is:

(4)

If we know that and , then the resulting velocity of the boat is:

The resulting velocity of the boat is .

0.55x745.7j and a calculator

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards