A ball of mass of 0.5kg is dropped from a height of 2m. Assuming that all of the GPE is transferred to KE, what
will be the velocity of the ball when it hits the ground?

6.3m/s

Explanation:

Given parameters:

Mass of the ball  = 0.5kg

Height  = 2m

Unknown:

Velocity when the ball hits the ground  = ?

Solution:

Since the potential  energy is transformed into kinetic energy;

            P.E  = K.E

              mgh  = m v²

     cancelling m;

               gh  =   v²

                v² = 2gh

                v  = √2gh

Insert the parameters and solve;

               v  = √2gh  = √ 2 x 9.8 x 2  = 6.3m/s

explanation:

specific heat is the amount of heat required to raise the temperature of a unit mass of a substance.

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)