If you increase the number of slits in an array (but keep the spacing between adjacent slits the same), what happens to the diffraction pattern? a. The number of bright fringes decreases.
b. The number of bright fringes increases.
c. The width of the bright fringes decreases.
d. The distance between the centers of the bright fringes increases.
e. The distance between the centers of the bright fringes decreases.
f. The width of the bright fringes increases.

Letter a, because when there are unlike charges they will always attract to each other.

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.