Physics, 09.11.2020 16:50 bluebabyyy

Cual es la fuerza electrica sobre el electrón (-1.6 x 10¹⁹c) de un atomo de hidrógeno ejercida por el protón (1.6 x 10¹⁹c)? Supóngase que la distancia entre el electrón y el proton es de 5.3 x 10¹¹ m

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Answer from: noah12345678

La fuerza eléctrica es -8.2*10⁻⁸ N

Explanation:

El enunciado correcto es: ¿Cuál es la fuerza eléctrica sobre el electrón (-1.6 x 10⁻¹⁹c) de un átomo de hidrógeno ejercida por el protón (1.6 x 10⁻¹⁹c)? Supóngase que la distancia entre el electrón y el protón es de 5.3 x 10⁻¹¹ m

Entre dos o más cargas aparece una fuerza denominada fuerza eléctrica. Su valor depende del valor de las cargas y de la distancia que las separa, mientras que su signo depende del signo de cada carga. Las cargas del mismo signo se repelen entre sí, mientras que las de distinto signo se atraen.

La fuerza eléctrica con la que se atraen o repelen dos cargas puntuales en reposo es directamente proporcional al producto de las mismas e inversamente proporcional al cuadrado de la distancia que las separa:

$F=K*\frac{q1*q2}{d^{2} }$

donde:

F es la fuerza eléctrica de atracción o repulsión. En el Sistema Internacional (S.I.) se mide en Newtons (N). q1 y q2 son lo valores de las dos cargas puntuales. En el S.I. se miden en Culombios (C). d es el valor de la distancia que las separa. En el S.I. se mide en metros (m). K es una constante de proporcionalidad llamada constante de la ley de Coulomb. Depende del medio en el que se encuentren las cargas. Para el vacío K tiene un valor aproximadamente de 9*10⁹ $\frac{N*m^{2} }{C^{2} }$ .

En este caso:

F=?K= 9*10⁹ $\frac{N*m^{2} }{C^{2} }$ q1= -1.6*10⁻¹⁹ Cq2= 1.6*10⁻¹⁹ Cd= 5.3*10⁻¹¹ m

Reemplazando:

$F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{(-1.6*10^{19} C)*(1.6*10^{19} C)}{(5.3*10^{-11} )^{2} }$

Resolviendo:

F= -8.2*10⁻⁸ N

La fuerza eléctrica es -8.2*10⁻⁸ N

Answer from: Quest

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