Ley de Gravitación (5 pts c/u) 2. Supongamos que una masa de 750 kg y otra de 600 kg se atraen en el vacío, separadas
por un espacio de 2.3 metros. ¿Cómo podemos calcular la fuerza de atracción que
experimentan?
3. A qué distancia debemos colocar dos cuerpos de masa de 4 kg y 7 kg, para que se
atraigan con una fuerza de 11 N?

What formula  this one  (x_/

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j