The position of a particle as a function of time is given by x=(−5m/s)t+(3m/s2)t2. Find the average speed from t=0 to t=1s.
Express your answer using two significant figures.
The position of a particle as a function of time is given by x=(−5m/s)t+(3m/s2)t2.

A100 kg running back runs at 5m/s into a stationary linebacker. it takes 0.5 for the running back to be completely stopped

Aparticle's position is given by x = 3.00 - 9.00t + 3t2, in which x is in meters and t is in seconds. (a) what is its velocity at t = 1 s? (b) is it moving in the positive or negative direction of x just then? (c) what is its speed just then? (d) is the speed increasing or decreasing just then? (try answering the next two questions without further calculation.) (e) is there ever an instant when the velocity is zero? if so, give the time t; if not, answer "0". (f) is there a time after t = 3 s when the particle is moving in the negative direction of x? if so, give the time t; if not, answer "0".

Photons with the highest energy have the longest period