A celebrated Mark Twain story has motivated contestants in the Calaveras County Jumping Frog Jubilee, where frog jumps as long as 2.20 m have been recorded. If a frog jumps 2.20 m and the launch angle is 46.5°, find the frog's launch speed and the time the frog spends in the air. Ignore air resistance.

4.7m/s and 0.54s

Explanation:

Using

R= u²sino2စ /g

2.2= u² sin2(46.5)/10

U²= 22

U= √22

=4.7m/s is the launch speed

Then time

T= 2usinစ/g

= 4.7*2sin46.5/10

0.54seconds

it's when something is going so fast it makes a loud noise, breaking the sound barrier, for example: a jet makes a loud noise, not only cause of the jet but because they reached a point where they went so fast that you can year the noise from various parts, kinda like a police car, lets say the car was going   so fast that you hear the siren of the cop car right next to you, but the car is probably a mile a way, it's cos the siren was next to you a few seconds if you understand me