A woman is standing in the ocean, and she notices that after a wavecrest passes, five more crests pass in a time of 50.0 s. Thedistance between two successive crests is 32 m. Determine, ifpossible, the wave’s (a) period, (b) frequency, (c) wavelength, (d) speed, and (e) amplitude. If it is not possible todetermine any of these quantities, then so state. I gotT=50/5 = 10sf=1/T = 0.1Hzv=f/lamda = 0.1/32 = 4.93m/s

(a) T = 10 s

(b) f = 0.1 Hz

(c) λ = 32 m

(d) v = 3.2 m/s

(e) Insufficient data

Explanation:

(a)

Time period is defined as the time interval required for one wave to pass. Therefore, the time period can be given as:

T = Period = Time Taken/No. of Waves

T = 50 s/5

T = 10 s

(b)

Frequency is the reciprocal of time period:

f = frequency = 1/T

f = 1/10 s

f = 0.1 Hz

(c)

Wavelength is the distance between two consecutive crests or troughs:

λ = Wavelength = 32 m

(d)

Speed of wave is given by the following formula:

Speed = v = fλ

v = (0.1 Hz)(32 m)

v = 3.2 m/s

(e)

Amplitude cannot be found with given data.

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answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg