A catapult launches a large stone from ground level at a speed of 45.2 m/s at an angle of 57.0° with the horizontal. The stone returns to ground level shortly thereafter. (a) How long is it in the air
s
(b) What maximum height does the stone reach? (Neglect air friction.)
Im

a

b

Explanation:

From the question we are told that

   The speed is  

   The angle is      

Generally the velocity of the stone in the y-axis is mathematically evaluated as

=>    

=>      

Now  the time taken for the first flight is mathematically represented as

=>      

=>      

The time taken for the total flight is mathematically represented as

From the equation of kinematics we have that  

At maximum heigth v =  0

      The  negative sign is because it is moving against gravity to attain the maximum height

So

trig 15.3 cos

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