Fluid flows at 2.0 m/s through a pipe of diameter 3.0 cm. What is the volume flow rate of the fluid?

The volume flow rate of the pipe is 1.41 x 10⁻³ m³/s

Explanation:

Given;

velocity of the fluid, v = 2.0 m/s

diameter of the pipe, d = 3.0 cm = 0.03 m

The volume flow rate is given by;

Q = Av

Where;

A is the area of the pipe

v is the velocity of the fluid

circular surface Area of the pipe is given by;

A = ¹/₄ πd²

A = ¹/₄ π(0.03)² = 7.07 x 10⁻⁴ m²

Q = (7.07 x 10⁻⁴)(2)

Q = 1.41 x 10⁻³ m³/s

Therefore, the  volume flow rate of the pipe is 1.41 x 10⁻³ m³/s

answer; /// the above statement is (true);

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.