A ball rolled at a velocity of 12 m/sec. After 36 seconds, it comes to a stop. What is the acceleration of the ball? Round to the nearest tenth.

Solving the problem mathematically,

Initial velocity of the ball 12m/s

Final velocity 0m/s

Travel time 36s

Assuming the velocity follows a straight line, then the slope of the curve is equal to the rate of change of velocity (acceleration)

ie taninv(dv/dt) since it is linear taninv(12/33)= 0.33 m/s^2 deceleration.

If in case the velocity doesn’t follow the linear path acceleration= d(velocity profile)/dt. ie the first order differentiation of velocity is the acceleration.

its a 5.5 n

glad that