Air contains 78.08% nitrogen, 20.095% oxygen, and 0.93% argon. a sample of air occupies 8 l at 273 k and applies a pressure of 2.45 atm to its container. the sample of air is heated to 550 k, at which time it takes up 11.8 l. what is the partial pressure of nitrogen after the air has been heated

the partial pressure of nitrogen after the air has been heated is 2.61atm

Explanation:

Using combined gas law which is the combination of Boyle's Law and Charles' Law, and it gives The relationship between pressure, volume, and absolute temperature

PV/T= K

P1₁V₁/T₁=P₂V2₂/T₂

P₂=final pressure= ?

P₁= initial pressure=2.45 atm

.T₁= initial temperature= 273k

T₂= final temperature= 550 K,

We can make P₂ subject of the formula then we have

P₂=P₁V₁T₂/T₁T₂

=( 2.45×8×550)/(273×11.8)

P2=3.35atm

Now we can calculate the partial pressure of N₂

N₂= 3.35×(78.08/10)

=2.61atm

Therefore, the partial pressure of nitrogen after the air has been heated is 2.61atm

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.