A force of 7.0 N acts on a block of wood at an angle of 50 degrees above the horizontal as the block moves a distance of 6.4 meters to the right. Calculate the work done on the block by the force

The work done on the block of wood by the applied force is 28.8 J.

The given parameters;

The work done on the block of wood by the applied force is calculated as follows;

W = F x dcosθ

W = 7 x 6.4 x cos(50)

W = 28.8 J

Thus, the work done on the block of wood by the applied force is 28.8 J.

Learn more here:link

28.796 J

Explanation:

I hope that it's a correct answer.

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.