A 4.0 kg block is resting on a rough horizontal table. The coefficient of static friction us is 0.60. The static friction between the block and the table before any attempted motion is to start is N. (round to the nearest integer)

The static friction between the block and the table before any attempted motion is to start equals 23.52 Newton.

Given the following data:

To determine the static friction between the block and the table before any attempted motion is to start:

Mathematically, the force of static friction is given by the formula;

  ...equation 1.

Where;

But,

  ...equation 2.

Substituting the given parameters into eqn. 2, we have;

Force of static friction = 23.52 Newton

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24 N

Explanation:

Given that the

Mass m = 4 kg

Coefficient of friction (μ) = 0.60

To calculate the static friction between the block and the table before any attempted motion, you will use the formula; F = (μ)N

Where

F = static friction

N = normal reaction = mg

g = acceleration due to gravity = 9.8 m/^2

Substitutes m, g and (μ) into the formula

F = 0.6 × 4 × 9.8

F = 23.52 N

Therefore, the static friction between the block and the table before any attempted motion is 24 N approximately.

50 inches should be the resultant vector

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