Aspring has a spring stiffness constant, k, of 440 n/m. how much must the spring be stretched to store 25 j of potential energy?

The spring is stretched by 33.7 cm.

Explanation:

It is given that,

Spring constant, k=440 N/m.

Energy stored in the stretched spring, E=25 J.

Now, Spring potential energy when it is stretched x meters is  

Therefore,

The spring is stretched by 33.7 cm.

Hence, this is the required solution.

that would be b i just took the test : )