A 121 turn 121 turn circular coil of radius 2.85 cm 2.85 cm is immersed in a uniform magnetic field that is perpendicular to the plane of the coil. Over an interval of 0.179 s 0.179 as, the magnetic field strength increases from 55.1 mT 55.1 mT to 97.9 mT 97.9 mT. Find the magnitude of the average emf E avg Avg induced in the coil during this time interval, in millivolts.

The magnitude of the average EMF = 73.83 mv

Explanation:

From faradays law of induction, EMF is given as;

EMF = NA(ΔB/Δt)

We are given that;

N = 121 turns

B1 = 55.1 mT

B2 = 97.9 mT

Thus, ΔB = 97.9 mT - 55.1 mT = 42.8 mT

t = 0.179 s

r = 2.85cm = 0.0285 m

Area = πr² = π x (0.0285)² = 0.0025518 m²

Plugging in the relevant values, we can calculate EMF as;

EMF = (121)(0.0025518)(42.8 mT/0.179) = 73.83 mv

50 inches should be the resultant vector

the answer is a 3.8cm

explanation: