A rocket-driven sled running on a straight, level track is used to investigate the effects of large accelerations on humans. One such sled can attain a speed of 1600 km/h in 2.20 s, starting from rest. Find (a) the acceleration (assumed constant) in terms of g and (b) the distance traveled.

a = 20.5931 g,

D = 488.88 meters

Explanation:

We can find acceleration using the formula

V = Vo + a*t, where V is the final speed, Vo is the inicial speed, a is the acceleration and t is time.

First, we need to convert the speed to meter/seconds:

V = 1600 km/h = 1600/3.6 m/s = 444.44 m/s

Then, using Vo = 0 (starts from rest), we have:

444.44 = 0 + a*2.2

a = 444,44/2.2 = 202.0182 m/s2

In terms of g (g=9,81 m/s2), we have that:

a = 202.0182/9.81 g = 20.5931 g

To find the distance travelled, we can use  Torricelli's equation:

V^2 = Vo^2 + 2*a*D, where D is the distance travelled. So:

444.44^2 = 0^2 + 2*202.0182*D

D = 197526.91/404.0364 = 488.88 meters

idk sorry i only needs point for apex

explanation:

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever