A 1.2 kg object moving with a speed of 8.0 m/s collides perpendicularly with a wall and bounces off with a speed of 6.0 m/s in the opposite direction. If the object is in contact with the wall for 2.0 milliseconds, what is the magnitude of the average force on the object by the wall

Average force will be equal to 8400 N

Explanation:

We have give mass of the object m = 1.2 kg

Initial velocity of the object u = - 8 m/sec

And after collision to the wall final velocity of the object v = 6 m/sec

Change in momentum is equal to

Time is given t = 2 milliseconds = 0.002 sec

We know that force is equal to rate of change of momentum

So

So average force will be equal to 8400 N