Two isolated, concentric, conducting spherical shells have radii R1 = 0.520 m and R2 = 1.40 m, uniform charges q1 = +2.50 μC and q2 = +2.70 μC, and negligible thicknesses. What is the magnitude of the electric field E at radial distance (a) r = 4.80 m, (b) r = 0.710 m, and (c) r = 0.210 m? With V = 0 at infinity, what is V at (d) r = 4.80 m, (e) r = 1.40 m, (f) r = 0.710 m, (g) r = 0.520 m, (h) r = 0.210 m, and (i) r = 0?

A) E = 2031.7 N/C

B) E = 44,643.8 N/C

C) E = 0 N/C

D) V = 9752.14 N/C

E) V = 33,435.91 N/C

F) V = 49,058 N/C

G) V = 60,639.65 N/C

H) V = 60,639.65 N/C

I) V = 60,639.65 N/C

Explanation:

We shall make use of the following;

At r < R1; E_in = 0 - - - - - (eq1)

At R1 < r < R2 ;

E_bet = q1/(4πε_o(r²)) -- - - - - (eq2)

At R1 < r < R2 ;

E_out = (q1 + q2)/(4πε_o(r²)) - (eq3)

At R1 < r < R2 ;

V_in = [1/(4πε_o)]•[(q1/R1) + (q2/R2)] - - - - - (eq4)

At R1 < r < R2 ;

V_bet = [1/(4πε_o]•[(q1/r) + (q2/R2)] - - - - - (eq5)

At r > R2 ;

V_out= (q1 + q2)/(4πε_o(r)) - - - - - (eq6)

A) r = 4.80 m. This falls into r > R2. But since we are looking for electric field, E, we will use eq (3)

Thus, E = (q1 + q2)/(4πε_o(r)²)

q1 = +2.50 μC = 2.5 x 10^(-6) C

q2 = 2.7 μC = 2.7 x 10^(-6) C

ε_o = 8.84 x 10^(-12) F/m

E = [(2.5 x 10^(-6))] + (2.7 x 10^(-6))] /(4πx8.84 x 10^(-12)x(4.8)²)

= 2031.7 N/C

B) r = 0.710 m, we'll use eq (2)

E_bet = q1/(4πε_o(r²))

E_bet = [2.5 x 10^(-6)]/(4πx8.84 x 10^(-12)x(0.71²)) = 44,643.8 N/C

C) r = 0.210 m

This corresponds with condition for eq 1 where enclosed charge is zero.

Thus, E_in = 0 N/C

D) V at r = 4.80 m

Corresponds to eq(6) where;

V_out= (q1 + q2)/(4πε_o(r))

Thus,

V_out = [(2.5 x 10^(-6))] + (2.7 x 10^(-6))] /(4πx8.84 x 10^(-12)x(4.8)) = 9752.14 N/C

E) V at r = 1.40 m

Corresponds with condition for eq(6)

V_out= (q1 + q2)/(4πε_o(r))

Thus,

V_out = [(2.5 x 10^(-6))] + (2.7 x 10^(-6))] /(4πx8.84 x 10^(-12)x(1.4)) 33,435.91 N/C

F) r = 0.710 Corresponds with condition for eq(5)

Thus,

V_bet = [1/(4πx8.84 x 10^(-12))]•[(2.5 x 10^(-6)/0.71) + (2.7 x 10^(-6)/1.4)] = 97318.13 N/C = 49,058 N/C

G) V at r = 0.520 m corresponds with condition for eq(5)

Thus,

V_bet = [1/(4π x 8.84 x 10^(-12))]•[(2.5 x 10^(-6)/0.52) + (2.7 x 10^(-6)/1.4)] = 60,639.65 N/C

H) V at r = 0.210 m corresponds with condition for eq(4)

V_in = [1/4πε_o]•[(q1/R1) + (q2/R2)] - - - - - (eq4)

Thus,

V_in = [1/(4π x 8.84 x 10^(-12))]•[(2.5 x 10^(-6)/0.52) + (2.7 x 10^(-6)/1.4)]

= 60,639.65 N/C

I) V at r = 0 m corresponds with condition for eq(4)

V_in = [1/4πε_o]•[(q1/R1) + (q2/R2)] - - - - - (eq4)

Thus,

V_in = [1/(4π x 8.84 x 10^(-12))]•[(2.5 x 10^(-6)/0.52) + (2.7 x 10^(-6)/1.4)]

= 60,639.65 N/C

there is no correct list among the choices you've provided.

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-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

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the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this