Bullets bounce from Superman's chest. Suppose that Superman, with mass 104 kg, while not moving, is struck by a 3.93 g bullet moving with a speed of 855 m/s. The bullet drops straight down with no horizontal velocity. How fast was Superman moving after the collision if his superfeet are frictionless

Explanation:

mass of superman, M = 104 kg

initial velocity of superman, U = 0

mass bullet, m = 3.93 g

initial velocity of bullet, u = 855 m/s

Let the velocity of superman after hitting by the bullet is V.

M x 0 + m x u = M x V + m x 0

3.93 x 10^-3 x 855 = 104 x V

V = 0.032 m/s

i don't understand. explain it clearly

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.