Physics, 26.03.2020 01:57 shainaanderson24

The California sea lion is capable of making extremely fast, tight turns while swimming underwater. In one study, scientists observed a sea lion making a circular turn with a radius of 0.37 m while swimming at 4.0 m/s.

What is the sea lion's centripetal acceleration, in units of g?

What percentage is this acceleration of that of an F-15 fighter jet's maximum centripetal acceleration of 9g?

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Answer from: Wolfie215

The value of centripetal acceleration is 4.41g.

The centripetal acceleration is 49% of the maximum acceleration F-15 fighter plane.

Given data:

The radius of circular turn is, r = 0.37 m.

The speed lion during the turn is, v = 4.0 m/s.

The centripetal acceleration is the center seeking acceleration produced by the force acting on the body during motion in a circular path. And standard expression for the centripetal acceleration is,

$a =\dfrac{v^{2}}{r} \\\\a =\dfrac{4^{2}}{0.37}\\\\a = 43.24 \;\rm m/s^{2}$

We known that the value of g is $9.8 \;\rm m/s^{2}$ . So divide and multiply a with g as,

$a =\dfrac{43.24 \;\rm m/s^{2} \times g}{g} \\\\ a =\dfrac{43.24 \;\rm m/s^{2} \times g}{9.8 \;\rm m/s^{2}} \\\\a = 4.41g$

Thus, we can conclude that the value of centripetal acceleration is 4.41g.

And the percentage is this acceleration of that of an F-15 fighter jet's maximum centripetal acceleration of 9g is,

$=\dfrac{a}{9g} \times 100\\\\ =\dfrac{4.41g}{9g} \times 100\\\\=49\%$

Thus, we can conclude that the centripetal acceleration is 49% of the maximum acceleration F-15 fighter plane.

Learn more about the centripetal acceleration here:

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Answer from: tankddd

Acceleration of Sea Lion is 4.41 g

This is 49% of maximum jet acceleration given as a = 9g

Explanation:

As we know that the radius of the circular loop is given as

R = 0.37 m

The speed of the fish is given as

v = 4 m/s

Now the centripetal acceleration of the sea lion is given as

$a_c = \frac{v^2}{R}$

$a_c = \frac{4^2}{0.37}$

a_c = 43.2 m/s^2

as we know that

g = 9.8 m/s^2

so we have

a = 4.41 g

Now Percentage of this acceleration wrt maximum jet acceleration is given as

$P = \frac{4.41 g}{9g} \times 100$

P = 49 %

Answer from: Quest

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006 kilo calorie

then ,802.3 kilo joule will be = 802.3 $\times$ 0.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

Answer from: Quest

The earths atmosphere is made up of nitrogen and oxygensolids turning into gases is called sublimation.

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