A charge of 40 pC is distributed on an isolated spherical conductor that has a 4.0-cm radius. Point A is 1.0 cm from the center of the conductor and point B is 5.0 cm from the center of the conductor. Determine the electric potential difference VA – VB.

Given that the charge on the conductor is Q=40 x 10-12 C

radius is r=0.04m

the potential at an inner point is constant and is same as that on the sphere that is

Va=kQ/r

    =9 x 109 x40 x 10-12 /0.04

     =9V

the potential at a point R=0.05m is

Vb=kQ/R

    =9 x 109 x40 x 10-12 /0.05

     =7.2V

Hence the potential difference is Va-Vb=1.8V

Explanation:

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explanation:

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