Sam, whose mass is 71kg , takes off across level snow on his jet-powered skis. The skis have a thrust of 250N and a coefficient of kinetic friction on snow of 0.1. Unfortunately, the skis run out of fuel after only 10s. What is Sam's top speed? (Express Answer in 2 sig figures & correct units)How far has Sam traveled when he finally coasts to a stop? (Express Answer in 2 sig figures & correct units)

Sam's top speed = 25 m/s

Distance Sam travels before coastring to a stop = 360 m

Explanation:

The thrust from the skis = 250 N

Frictional force on Sam = coefficient of friction × Sam's weight

                                       = (0.1)(71 kg)(9.8 m/s²) = 69.58 N

The effective force moving Sam = 250 N - 69.58 N = 180.42 N

The acceleration of Sam due to this force = 180.42 N ÷ 71 kg = 2.54 m/s²

Sam starts from rest. Initial velocity, u = 0 m/s. The skis run out after time, t = 10 s.

Using the equation of motion,

v = u + at

v = 0 + (2.54 m/s²)(10 s) = 25.4 m/s ≈ 25 m/s

This is Sam's top speed.

v² = u² + 2as

The distance travelled while the skis were working is determined using the equation of motion

For the stopping motion, his initial velocity is 25.4 m/s and final velocity = 0 m/s. His acceleration is determined by the frictional force since there is no thrust from the skis.

a = -69.58 N ÷ 71 kg = -0.98 m/s²

(It is negative because it acts in opposite direction to the velocity)

Using the equation of motion

v² = u² + 2as

Total distance travelled = 32.92 m + 329.16 m = 362.08 m ≈ 360 m

the answer is a 3.8cm

explanation:

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.