A harmonic wave travels in the positive x direction at 12 m/s along a taught string. A fixed point on the string oscillates as a function of time according to the equationy = 0.0205 cos(4t)where y is the displacement in meters and the time t is in seconds(a) What is the amplitude of the wave, in meters?(b) What is the frequency of the wave, in hertz?(c) What is the wavelength of the wave, in meters?

Amplitude, A = 0.0205 m

Frequency, f = 0.636 Hz

Wavelength, 18.84 m

Explanation:

Given that,

Speed of the wave along a taught string, v = 12 m/s

A fixed point on the string oscillates as a function of time according to the equation :

........(1)

Here, y is the displacement in meters and the time t is in seconds

The general equation of oscillation is given by :

............(2)

On comparing equation (1) and (2) we get :

(a) Amplitude, A = 0.0205 m

(b) Frequency of the wave,

(c) Velocity of the wave is given by formula as :

Since,

Hence, this is the required solution.

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2