A voltage source of 10.0 V is connected to a series RC circuit where R = 2.80 × 10 6 Ω, and C = 3.50 µF. Find the amount of time required for the current in the circuit to decay to 4.00% of its original value. Hint: This is the same amount of time for the capacitor to reach 96.0% of its maximum charge.

The amount of time is 31.45 sec.

Explanation:

Given that,

Voltage = 10.0 V

Resistance

Capacitance

We need to calculate the time constant

Using formula of time constant

Put the value into the formula

The amount of time required for the current in the circuit to decay to 4.00% of its original value.

We need to calculate the amount of time

Using formula of charge

Put the value into the formula

Hence, The amount of time is 31.45 sec.

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.

current flows in a wire