15kg cat initially traveling +2m/s accelerates at +2m/s2 for 5 seconds how much kinetic energy does it again?
A. 1050J
B. 30J
C. 500J
D. 1080J

A) 1050[J]

Explanation:

First, we must calculate the initial kinetic energy when the cat moves at 2 [m/s].

Then we can calculate the final velocity with the acceleration and time data that was given.

And we can calculate the kinetic energy as follows:

And now we can calculate the difference in kinetic energy by simply subtracting the values calculated above.

DE = 1080 - 30 = 1050[J]

0.19 m/s and 0.45 m/s

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures