Acharge of -3.50 nc is placed at the origin of an xy-coordinate system, and a charge of 1.95 nc is placed on the y axis at y = 3.75 cm .find the distances to the center.

3.72 cm

Explanation:

the coordiante of the negative charge =( 0,0)

the  coordinate of the positive charge = (0,3.75)

the distance simply is  3.72-0 = 3.72 cm

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

report!

explanation:

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