At time t = 0 s, an object is observed at x = 0 m; and its position along the x-axis follows this expression: x = –4t + t2, where the units for distance and time are meters and seconds, respectively. what is the object's displacement between t = 1.0 s and t = 3.0 s?

The object displacement is 0 meters.

Explanation:

Because the expression for the object position as function of time is:

At t= 3.0=t2 seconds the x-position of the object is:

and at t=1.0=t1 seconds the x-position of the objects is:

The total displacement () of the object between t2 and t1 is the difference between x(3.0s) and x(1.0s):

The displacement of the object is zero!!!