A555 g ball strikes a wall at 14.9 m/s and rebounds at 12.1 m/s. the ball is in contact with the wall for 0.044 s. what is the magnitude of the average force acting on the ball during the collision?

Explanation:

Force is given by rate of change of momentum.

Mass of bullet = 555 g = 0.555 kg

Initial velocity = 14.9 m/s

Final velocity = -12.1 m/s - Opposite direction

Change in momentum = 0.555 x 14.9 - 0.555 x (-12.1)

Change in momentum = 14.985 kg m/s

Time taken = 0.044 s

Rate of change of momentum = Change in momentum ÷ Time

Rate of change of momentum = 14.985 ÷ 0.044

Rate of change of momentum = 340.57 N

Force = 340.57 N

The magnitude of the average force acting on the ball during the collision is 340.57 N

when the velocity of a mass on a spring is zero, the acceleration is at a maximum .