An electron is accelerated uniformly at a rate of 25,000 km/s from rest in an accelerator, over a distance of 125 km. what is the final velocity of the electron?

2500km/s

Explanation:

use equation wich conects distance and  acceleration:

S=Vst+at²/2

Vs=0km/s(from rest)

S=at²/2

S2=at²

t=√2S/a

t=√2*125km/25000 km/s²

t=0.1s

Vf --final velocity

Vs-- start velocity

a=Vf-Vs/t

at=Vf-Vs

Vs=0Km/s

at=Vf

25000Km/s*0.1s=Vf

Vf=2500Km/s

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

1 the 4 is sig