Au-tube is filled with water until the liquid level is 28cm above the bottom of the tube. an oil of specific gravity 0.78 is now poured into one arm of the u-tube until the level of the water in the other arm of the tube is 34 cm above the bottom of the tube. find the level of the oil-water and oil-air interfaces in the other arm of the tube.

Answer

given,

height of water = 28 cm

specific gravity of the oil = 0.78

new height of the water level = 34 cm

height of water = ?

increase in height = 34 - 28 = 6 cm

water oil interface is at = 28 - 6 = 22 cm

so, now, 12 cm of weight of water is to be displaced by oil

height of the equivalent oil

      = 12 / 0.78

      = 15.38 cm

height of the oil from the bottom is equal to

     = 22 + 15.38

     = 37.38 cm

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