You throw a 0.150-kg baseball straight up in the air, giving it an initial upward velocity of magnitude 20.0 m/s. how high does the ball rise? (ignore the effect of air resistance.)

3.00 m

133 m

14.7 m

20.4 m

Option D

20.4 m

Explanation:

Applying the law of conservation of energy

initial kinetic energy = final potential energy

where m is the mass, v is the velocity, g is acceleration due to gravity and h is the height.

Making height the subject then

Substituting the given value of v as 20 m/s and using acceleration of 9.81 then

god i hope this !