Paintball guns were originally developed to mark trees for logging. a forester aims his gun directly at a knothole in a tree that is 4.0 m above the gun. the base of the tree is 15 m away. the speed of the paintball as it leaves the gun is 50 m/s. how far below the knothole does the paintball strike the tree? express your answer with the appropriate units.

The distance between knothole and the paint ball is 0.483 m.

Explanation:

Given that,

Height = 4.0 m

Distance = 15 m

Speed = 50 m/s

The angle at which the forester aims his gun are,

Using the equation of motion of the trajectory

The horizontal displacement of the paint ball is

Using the equation of motion of the trajectory

The vertical displacement of the paint ball is

Put the value into the formula

We need to calculate the distance between knothole and the paint ball

Hence, The distance between knothole and the paint ball is 0.483 m.

i think it's 35 meters

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west