Acar traveling 23 m/s begins to decelerate at a constant rate of 5 m/s^2 . after how many seconds does the car come to a stop? (use symbolic notation and fractions where needed.)

t = 4.6 s

Explanation:

given,

initial velocity of the car = 23 m/s

declaration rate of car = 5 m/s²

final velocity of the car = ?

time taken to stop the car = ?

using equation of motion to solve the question

v = u + a t

v is final velocity

u is the initial velocity

0 = 23 - 5 t

we have used negative sign because there is deceleration

5 t = 23

t = 4.6 s

time taken to stop the car is equal to t = 4.6 s

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