During a very quick stop, a car decelerates at 6.8 m/s^2. assume the forward motion of the car corresponds to a positive direction for the rotation of the tires (and that they do not slip on the ) what is the angular acceleration of its 0.280-m-radius tires, assuming they do not slip on the pavement? (b) how many revolutions do the tires make before coming to rest, given their initial angular velocity is 95.0 rad/s ? (c) how long does the car take to stop completely? (d) what distance does the car travel in this time?

-24.28571 rad/s²

29.57239 revolutions

3.91176 seconds

52.026478 m

Explanation:

= Tangential acceleration = -6.8 m/s²

r = Radius of wheel = 0.28

= Initial angular velocity = 95 rad/s

= Angle of rotation

= Final angular velocity

t = Time taken

Angular acceleration is given by

The angular acceleration is -24.28571 rad/s²

The number of revolutions is 29.57239

The time it takes for the car to stop is 3.91176 seconds

Linear distance

The distance the car travels is 52.026478 m

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.