Physics, 10.12.2019 01:31 mimithurmond03
During a very quick stop, a car decelerates at 6.8 m/s^2. assume the forward motion of the car corresponds to a positive direction for the rotation of the tires (and that they do not slip on the ) what is the angular acceleration of its 0.280-m-radius tires, assuming they do not slip on the pavement? (b) how many revolutions do the tires make before coming to rest, given their initial angular velocity is 95.0 rad/s ? (c) how long does the car take to stop completely? (d) what distance does the car travel in this time?
Answers: 3
= Tangential acceleration = -6.8 m/s²
= Initial angular velocity = 95 rad/s
= Angle of rotation
= Final angular velocity
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During a very quick stop, a car decelerates at 6.8 m/s^2. assume the forward motion of the car corre...
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