Achild is holding a ball with a diameter of 5.70 cm and average density of 0.0835 g/cm3 under water. determine the force (in n) needed to hold it completely submerged.

0.488 N

Explanation:

Given , The ball has diameter (d)=5.70 cm = 0.0570 m

radius(r) = d/2 = 2.85 cm = 0.0285 m

Average density

There are two forces acting on the ball.. i.e. The buoyancy force and weight of the ball.

The force required to completely submerged under water= Buoyancy force - Weight of ball

buoyancy force = volume×density of water×g

[ density of water = 1000 kg/m3]

=0.532 N

mass of ball = average density×Volume

= 0.004529 kg

Weight of ball = mg = 0.004529×9.81 =0.044 N

Required force = 0.532 - 0.044 = 0.488 N.

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the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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