Acoin which is tossed straight up into the air. after it is released it moves upward, reaches its highest point and falls back down again. air resistance can be neglected. what force acts upon the coin when it is at its highest point?

a. force acting up and increasing
b. force acting up and constant
c. force acting down and decreasing
d. force of zero
e. force acting down and increasing
f. force acting down and constant
g. force acting up and decreasin

f. Force acting down and constant

Explanation:

At the highest point, the coin will start to free fall and in free fall only force of gravity act, which is always acted downward and its magnitude is mass times g. g=9.81 m/s^2. which makes the force constant.

therefore, the correct answer will be f. Force acting down and constant

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

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