Acannon fires a shell straight upward; 1.7 s after it is launched, the shell is moving upward with a speed of 17 m/s. assuming air resistance is negligible, a.find the speed (magnitude of velocity) of the shell at launch and 5.5 s after the launch
(b) 5.5 s after the launch

a) 0.323m/s b) 54.278 m/s

Explanation:

The shell is moving upward with a speed of 17m/s

1.7s after it was launch

Using equation of motion on a straight line,

Vfinal = Vintial + acceleration due to gravity *time

Where V represent the speed(velocity)

Vinital = V(at 1.7s) - 9.81* 1.7

Vinital = 17 - 16.677

a) Vinital = 0.323m/s

b) using the same equation,

V(after 5.5s) = Vinital + 9.81*5.5s

Vafter5.5s = 0.323 + 53.955

V after 5.5s = 54.278m/s

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles

causes

fossil fuels burn

cities become more industrialized

human population grows worldwide