![\log{\dfrac{\sqrt[3]{2-x}}{3x}}=\log{\sqrt[3]{2-x}}-\log{3x}=\dfrac{1}{3}\log{(2-x)}-\log{(3x)}](/tpl/images/0057/5224/a4a39.png)
how would you write the following expression as a sum or difference?
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Mathematics, 06.07.2019 10:10 kenziekey831
how would you write the following expression as a sum or difference?
Answers: 1
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