Two 1.50-v batteries—with their positive terminals in the same direction—are inserted in series into the barrel of a flashlight. one battery has an internal resistance of 0.320 ω, the other an internal resistance of 0.140 ω. when the switch is closed, a current of 600 ma occurs in the lamp. (a) what is the bulb's resistance?

Explanation:

It is given that,

Voltage of the battery, V = 1.5 V

Internal resistance of battery 1,

Internal resistance of battery 2,              

Current flowing in the lamp,

Total internal resistance of tow batteries,

Let R is the resistance of the bulb. Let V is the total emf of the circuit. It is given by :

So, the resistance of the bulb is 4.54 ohms. Hence, this is the required solution.                            

terd muffin is the correct answer

kepler used the data from tycho blahe (his mentor) to construct the laws of planetary motion.