A300 g block connected to a light spring with a force constant of k = 3 n/m is free to oscillate on a horizontal, frictionless surface. the block is displaced 3 cm from equilibrium and released from rest. find the period of its motion. (recall that the period, t, and frequency, f, are inverses of each other.)

Time period, T = 1.98 seconds

Explanation:

It is given that,

Mass of the block, m = 300 g = 0.3 kg

Force constant of the spring, k = 3 N/m

Displacement in the block, x = 3 cm

Let T is the period of the motion of the block. The time period of the block is given by :

T = 1.98 seconds

So, the period of the motion of the block is 1.98 seconds. Hence, this is the required solution.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures