Calculate the ratio of the drag force on a passenger jet flying at an altitude of 10 km to the drag force on a prop-driven plane flying at two-fifths the speed and half the altitude of the jet. at 10 km the density of air is 0.380 kg/m3 and at 5.0 km it is 0.670 kg/m3. the prop-driven plane has one-third the cross-sectional area of the passenger jet. the passenger jet has two-fifths the drag coefficient of the prop-driven plane.

2.268

Explanation:

The concepts that we need to use here for give a solution are Drag coefficient and drag force.

Drag force is given by,

Where,

c is the drag coefficient

is the density

A cross sectional area

V the velocity.

Our values for this problem are divided for Passenger and Driver.

For Jet are:

For prop-driven are:

From the problem we need to assume that and , THEN

Applying to each case the Drag force equation we have,

The ratio between the two force is,

Therefore the force experienced by a Jet pilot under these conditions is 2,268 times greater than that of a prop-driven

nah.   i'm just sleepy.

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg