Aproton, with mass 1.67 x 10-27 kg and charge +1.6 x 10-19 c, is sent with velocity 7.1 x 104 m/s in the +x direction into a region where there is a uniform electric field of magnitude 730 v/m in the +y direction. assume that the magnetic field has no x-component and neglect gravitational effects. what is the magnitude and direction of the uniform magnetic field in the region, if the proton is to pass through undeflected?

B = 0.0102 T

Explanation:

given,                            

mass of proton =  1.67 x 10⁻²⁷ kg

charge of proton = 1.6 x 10⁻¹⁹ C

velocity = 7.1 x 10⁴ m/s in x-direction

Uniform electric field = 730 V/m in y- direction

equation of force in electric field

F = E q                          

equation of force in magnetic field

F = q V B                          

equating both force expression

E q= q V B                              

B = 0.0102 T

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

the electric field is a “force field” around a charged object that illustrates the direction the electric force would push an imaginary