Physics, 02.11.2019 03:31 CheddaDsk

Asolution contains ag and hg2 ions. the addition of 0.100 l of 1.10m nai solution is just enough to precipitate all the ions as agi and hgi2. the total mass of the precipitate is 25.5 g. find the mass of agi in the precipitate.

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Answer from: kayla65u

First we write out the balanced equation for this reaction. Note: Mercury(II) iodide is HgI2 and not HgI.

Ag+(aq) + Hg2+(aq) + 3I^-(aq) = AgI(s) + HgI2(s)

moles I^- added = (Molarity I^-)(L of I^-) = (1.10)(0.100) = 0.11moles I^- addedhe balanced equation indicates that Hg^2+ uses up twice as much I^- in the reaction as does Ag+, since the formula for HgI2 contains 2 I^- atoms while the formula for AgI contains only 1 I^- atom. Hence if Ag^+ consumes x moles of I-, then Hg2+ consumes 2x moles of I-. The total moles of I^- consumed = 3x = 0.11 moles I-.

3x = 0.11; x = 0.11/ 3 = 0.0367 moles I^-

0.0367moles I^- x (126.9 g I- / 1 mole I-) = 4.657 g I^-

The formula for AgI shows the that the mole ratio of Ag^+ to I^- is 1:1.

0.0367 moles I- x (1 mole Ag^+ / 1 mole I-) = 0.0367 moles Ag+

0.0367 moles Ag^+ x (107.9 g Ag / 1 mole Ag) = 3.960g Ag^+

So therefore the mass of AgI = mass of Ag^+ + mass of I- = 3.96 + 4.657 = 8.607 g AgI

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

Answer from: Quest

An atom's smaller negative particles are at a distance from the central positive particles, so the negative particles are easier to move.

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Asolution contains ag and hg2 ions. the addition of 0.100 l of 1.10m nai solution is just enough to...

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