Four rods that obey hooke's law are each put under tension. (a) a rod 50.0 cm long with cross-sectional area 1.00 mm2 and with a 200 n force applied on each end. a rod 25.0 cm long with cross-sectional area 1.00 mm2 and with a 200 n force applied on each end. 00 mm2 and with a 100 n on each end. (c) a rod 20.0 cm long with cross-sectional area 2 force applied order the rods according to the tensile stress on each rod, from smallest to largest. oc

   c <  a = b

Explanation:

to arrange tensile stress from smallest to largest

tensile stress =

a) A rod 50.0 cm long with cross-sectional area 1.00 mm² and with a 200 N force applied on each end.

b) A rod 25.0 cm long with cross-sectional area 1.00 mm² and with a 200 N force applied on each end.

c) A rod 20 cm long with cross-sectional area 2.00 mm² and with a 100 N force applied on each end.

hence the order comes out to be

   c <  a = b

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it