In a common but dangerous prank, a chair is pulled away as a person is moving downward to sit on it, causing the victim to land hard on the floor. suppose the victim falls by 0.40 m, the mass that moves downward is 61.0 kg, and the collision on the floor lasts 0.0820 s. what are the magnitudes of the (a) impulse and (b) average force acting on the victim from the floor during the collision?

Given the relationships,

Given the energy conservation equation,

Since this is the initial speed and according to the problem, the final is zero,

\vec{J}=m(\vec{v}_f-\vec{v}_i)

B) The average force would be given by the change that exists at the time during the change of time,

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards